5a^2+8a+3=(a+1)

Solution for 5a^2+8a+3=(a+1) equation:

5a^2+8a+3=(a+1)

We move all terms to the left:

5a^2+8a+3-((a+1))=0


We calculate terms in parentheses: -((a+1)), so:

(a+1)

We get rid of parentheses

a+1

Back to the equation:

-(a+1)


We get rid of parentheses

5a^2+8a-a-1+3=0

We add all the numbers together, and all the variables

5a^2+7a+2=0

a = 5; b = 7; c = +2;
Δ = b2-4ac
Δ = 72-4·5·2
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-3}{2*5}=\frac{-10}{10}
=-1
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+3}{2*5}=\frac{-4}{10}
=-2/5
$